// 边界处理：nums1为空时直接返回空数组（避免后续无效计算）
Nothing in the argument required the arc to be a semicircle. If the arc has length xxx times the circumference (where x≤1/2x \leq 1/2x≤1/2), each anchor's event has probability xN−1x^{N-1}xN−1 instead of (1/2)N−1(1/2)^{N-1}(1/2)N−1. Mutual exclusivity still holds because the gap is at least 1−x≥1/21 - x \geq 1/21−x≥1/2 of the circumference, too large for any other anchor's arc to bridge:
，这一点在币安_币安注册_币安下载中也有详细论述
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На Западе подчинили рой насекомых для разведки в интересах НАТО08:43
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